2x^2+4x-6x-12=600

Solution for 2x^2+4x-6x-12=600 equation:

2x^2+4x-6x-12=600

We move all terms to the left:

2x^2+4x-6x-12-(600)=0

We add all the numbers together, and all the variables

2x^2-2x-612=0

a = 2; b = -2; c = -612;
Δ = b2-4ac
Δ = -22-4·2·(-612)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-70}{2*2}=\frac{-68}{4}
=-17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+70}{2*2}=\frac{72}{4}
=18
$